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A chances `36/91`B chances `5/6.(36)/(91)`C chances `(5/6)^(2)(36)/(91)`All three has same chances

Answer :

A::B::CTranscript

Time | Transcript |
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00:00 - 00:59 | hello friends we have a question here ABC in order roll a dice on condition that the one who gets 6 wins the winds then which of the following are true that is we have to find the age chances be chances and see chances of winning right so let so probability that is the probability for winning to any one of them that is to get a six to Probability to get a 6 equal to 1 by 6 and probability to not get 6 equal to 556 right now here |

01:00 - 01:59 | we will we will use a multiplication theorem here that is multiplication theorem theorem of compound probability that is we buy a equal to P of a intersection b upon P of P of a that mean when a already happen we have to find the probability of be so this is equal to P right now here we have 3 contestant ABC so we have to find the probability of so I will write as my that is a wins a wins in try that is first suppose they are playing the first wrong in |

02:00 - 02:59 | first round that even write suitability as a win and a start the game so probability of a wins in the first round that will be won by 6 but here we don't know that how many rounds they will play so will continue upto Infinity Round Right so there that's why the try be that is be wins in the Ayat try and see that is sea winds Hindi Ayat try now first we that they are playing in order that they will play first then we will play first then she will play first |

03:00 - 03:59 | then she will play right so probability for a events probability for events equal to that in first round that is probability of because a one is playing and if you got the 6 then he will automatically when in first round now in second round date when in first round so he will go for the second round in second round first a will play a will not get in second round a will play but a a not get the six so we will go for the b&b also not get the Knot 6 then we will go for the sea see also not get the sex then |

04:00 - 04:59 | who will come is a second round a second term will come right so in second round a got sex so he will he will win right similarly we will go and so on so that is in third round that a didn't win in second round as well so he will go for the third round when you go up to the third round that mean a will already play two times we will already played two times and she will already played two times so that is I am writing a didn't get didn't get a A1 B1 intersection C 1 bar intersection 82 by intersection b to bar intersection C to bar and intersection |

05:00 - 05:59 | 83 that a a got the number in 3rd round right now the probability of a one we will write that probability of a one like this now as I have I have made here so he can we can write this condition probability as a intersection b equal to P of a p of B by a ride now this A1 we can write this this we can write that this we can write fee of Avon bar pb11 / a |

06:00 - 06:59 | 17 / a bar intersection b bar into of a 2-1 intersection b 1 bar intersection C 1 this term is equal to this term as as if I have if I have that in theorem of compound probability if I have a number that is in this format that of a intersection b intersection C intersection b intersection and so on so we can write that is so on so we can write that of a of |

07:00 - 07:59 | BBA fee of C by a intersection b p off d by a intersection b intersection c and so on as like in we didn't conditional theorem that fee of of a intersection b we can write of a into B by in this in the above we have to term in the second we have Anthem understood so that's why we have written this we have applied this in a question write so we can write that this will be equal to P of a one piece of A1 A1 equal to |

08:00 - 08:59 | 1 by 6 right now in this condition P of Avon bar that is 5 by 6 of B1 Bar by Avon bar that is when even even buy 1 get 1 Avon bar happen then be won by happen tried so this is will be 556 when even in the section even by interaction B1 bhaiya happen then C1 bar happen this will be 5 by 6 right now when this all three happen it will be happen that is 1 by 6 similarly this one will be happen that that will come around 556 to the power 5 by 6 to the power 6 into 1 by 6 upto Infinity right now |

09:00 - 09:59 | we can see that that we will take 1 by 6 months is 1 + 5 by 6 to the power 6 and so on upto Infinity as we can see that the inside the term in bracket this is the sum of infinity in GP that is first term upon 1 minus common ratio as common ratio is 5.6 square so we can write 1 by 6 into first term is 1 divided by 1 minus 5 by 6 whole square 30 in ratio so we can write this will be equal to 1 by 6 that is 36 - 25 that is here is a cube the common ratio is common ratio is 5 by 6 cube so this will be to 16 - 125 that will be come 91 |

10:00 - 10:59 | into 6 Q this is equal to 6 square by 9144 the probability of winning a is 6 square by 91 that is 3691 so option is right now we will find the probability for be so probability for winning for be that probability be winds that is equal to in the first round a will get the first chance so I didn't get the 6 intersection b get the sex right now in second round in s the first round now we will go for the second round that if B1 if we didn't get the six in first term in first round so he will go for the second |

11:00 - 11:59 | round at suppose he get the Sikhs in second round for the probability will be free of a intersection b intersection C intersection b intersection a2ba intersection b to write and so on to infinity upto Infinity round for this we can write it as I'm not writing the that I'm so I am writing here that is fee of P of Avon ba1 bar + P of A1 Plus B1 by be one that is here fee of B 1 Bar |

12:00 - 12:59 | by Avon bar + t of 7 Bar by a one by intersection b 1 bar into of 82 82 82 bar intersection by Avon bar intersection b intersection C 1 bar in topi of B2 by Avon bar intersection b 1 bar intersection C 1 bar intersection A2 bar and so on right so this can write this will be 5 by 6 INR to 1 by 6 that is this will be 5 by 6 |

13:00 - 13:59 | into 5 by 6 into into 5 by 6 that is this will Tum this term we write this term now we will write this this is 5 by 6 into INR to 5.6 into 1 by 6 8 and so on upto Infinity so this we will get that will be we will take 1 by 6 month here we will come 5 by 6 + 5 by 6 to the power 4 + 5 by 6 to the power 7 and so on so this will form in fig Pritam inside the sum of infinity in GP so we will use a formula that is a upon 1 minus are |

14:00 - 14:59 | that is equal to 1 by 6 into 5 by 6 upon 1 minus 5 by 6 cube that is equal to 5 by 6 into 6 cube / 91 that will come 5 in 26 / 91 right so we can see from the option write this is option to is also write the chances for winning now we will go for we will check for the option will check for the chances so probability that she wins so that mean in first round that I didn't get 6 billion get 60 get 6 so this will be probability a inter save an intersection |

15:00 - 15:59 | b 1 intersection c c Sivan that is probability even by intersection B1 B1 B intersection C 1 now that if she didn't get in first round so he will go for the second round that is equal to A1 A1 by intersection b 1 bar intersection C 1 by intersection a182 intersection b Tuba intersection C to write and so on so this will be equal to 5 by 6 into 5.6 INR to 1 by 6 + 5 by 6 that they even happen 56 B1 happen 5 by 6 C1 |

16:00 - 16:59 | happen 5 by 6 to 12 happen and 5 6 b to B happen and 1 by 6 and so on so we will take 1 by 6 common this will come as 556 square this will come as 5 by 6 to the power 5 and so on upto Infinity so This Storm inside bracket is forming a GP with infinite GP so this is 1 by 6 that is equal to 1 by 6 into 5 by 6 whole square 5 by 6 whole square divided by 1 minus common ratio common ratio is 5 by 6 |

17:00 - 17:59 | whole cube that will become 5 square upon 6 cube into 91 and here in nominated will be 6 cube so this we got our answer for this evening so we will check for the option that option C is right answer is option 1 option 2 option 3 thank you |

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